Math Practice Online: MathScore.com

Math Practice Online > free > lessons > Texas > 6th grade > Estimated Addition

If your child needs math practice, click here.

These sample problems below for Estimated Addition were generated by the MathScore.com engine.

Sample Problems For Estimated Addition


Complexity=60

Estimate the sum using the highest practical magnitude.
Example 1: 53 + 19 => 50 + 20
Example 2: 123 + 57 => 120 + 60
Example 3: 1598 + 2301 => 2000 + 2000
1.  
19
+ 32
Estimate
2.  
47
+ 36
Estimate

Complexity=100

Estimate the sum using the highest practical magnitude.
Example 1: 53 + 19 => 50 + 20
Example 2: 123 + 57 => 120 + 60
Example 3: 1598 + 2301 => 2000 + 2000
1.  
44
+ 47
Estimate
2.  
75
+ 91
Estimate

Complexity=200

Estimate the sum using the highest practical magnitude.
Example 1: 53 + 19 => 50 + 20
Example 2: 123 + 57 => 120 + 60
Example 3: 1598 + 2301 => 2000 + 2000
1.  
102
+ 63
Estimate
2.  
111
+ 167
Estimate

Complexity=700

Estimate the sum using the highest practical magnitude.
Example 1: 53 + 19 => 50 + 20
Example 2: 123 + 57 => 120 + 60
Example 3: 1598 + 2301 => 2000 + 2000
1.  
411
+ 262
Estimate
2.  
583
+ 250
Estimate

Complexity=1000

Estimate the sum using the highest practical magnitude.
Example 1: 53 + 19 => 50 + 20
Example 2: 123 + 57 => 120 + 60
Example 3: 1598 + 2301 => 2000 + 2000
1.  
686
+ 695
Estimate
2.  
997
+ 702
Estimate

Complexity=5000

Estimate the sum using the highest practical magnitude.
Example 1: 53 + 19 => 50 + 20
Example 2: 123 + 57 => 120 + 60
Example 3: 1598 + 2301 => 2000 + 2000
1.  
3315
+ 3509
Estimate
2.  
3443
+ 4050
Estimate

Complexity=10000

Estimate the sum using the highest practical magnitude.
Example 1: 53 + 19 => 50 + 20
Example 2: 123 + 57 => 120 + 60
Example 3: 1598 + 2301 => 2000 + 2000
1.  
7402
+ 8573
Estimate
2.  
7086
+ 9135
Estimate

Complexity=20000

Estimate the sum using the highest practical magnitude.
Example 1: 53 + 19 => 50 + 20
Example 2: 123 + 57 => 120 + 60
Example 3: 1598 + 2301 => 2000 + 2000
1.  
18792
+ 19516
Estimate
2.  
10785
+ 9017
Estimate

Complexity=100000

Estimate the sum using the highest practical magnitude.
Example 1: 53 + 19 => 50 + 20
Example 2: 123 + 57 => 120 + 60
Example 3: 1598 + 2301 => 2000 + 2000
1.  
99872
+ 97079
Estimate
2.  
67284
+ 72255
Estimate

Answers


Complexity=60

Estimate the sum using the highest practical magnitude.
Example 1: 53 + 19 => 50 + 20
Example 2: 123 + 57 => 120 + 60
Example 3: 1598 + 2301 => 2000 + 2000
#ProblemCorrect AnswerYour Answer
1
19
+ 32
Estimate
Solution
To get the estimated answer, estimate each operand.
19 => 20
32 => 30
20 + 30 = 50
#ProblemCorrect AnswerYour Answer
2
47
+ 36
Estimate
Solution
To get the estimated answer, estimate each operand.
47 => 50
36 => 40
50 + 40 = 90

Complexity=100

Estimate the sum using the highest practical magnitude.
Example 1: 53 + 19 => 50 + 20
Example 2: 123 + 57 => 120 + 60
Example 3: 1598 + 2301 => 2000 + 2000
#ProblemCorrect AnswerYour Answer
1
44
+ 47
Estimate
Solution
To get the estimated answer, estimate each operand.
44 => 40
47 => 50
40 + 50 = 90
#ProblemCorrect AnswerYour Answer
2
75
+ 91
Estimate
Solution
To get the estimated answer, estimate each operand.
75 => 80
91 => 90
80 + 90 = 170

Complexity=200

Estimate the sum using the highest practical magnitude.
Example 1: 53 + 19 => 50 + 20
Example 2: 123 + 57 => 120 + 60
Example 3: 1598 + 2301 => 2000 + 2000
#ProblemCorrect AnswerYour Answer
1
102
+ 63
Estimate
Solution
To get the estimated answer, estimate each operand.
102 => 100
63 => 60
100 + 60 = 160
When numbers have different magnitudes, round each number to the next highest magnitude, such as in this problem.
#ProblemCorrect AnswerYour Answer
2
111
+ 167
Estimate
Solution
To get the estimated answer, estimate each operand.
111 => 100
167 => 200
100 + 200 = 300

Complexity=700

Estimate the sum using the highest practical magnitude.
Example 1: 53 + 19 => 50 + 20
Example 2: 123 + 57 => 120 + 60
Example 3: 1598 + 2301 => 2000 + 2000
#ProblemCorrect AnswerYour Answer
1
411
+ 262
Estimate
Solution
To get the estimated answer, estimate each operand.
411 => 400
262 => 300
400 + 300 = 700
#ProblemCorrect AnswerYour Answer
2
583
+ 250
Estimate
Solution
To get the estimated answer, estimate each operand.
583 => 600
250 => 300
600 + 300 = 900

Complexity=1000

Estimate the sum using the highest practical magnitude.
Example 1: 53 + 19 => 50 + 20
Example 2: 123 + 57 => 120 + 60
Example 3: 1598 + 2301 => 2000 + 2000
#ProblemCorrect AnswerYour Answer
1
686
+ 695
Estimate
Solution
To get the estimated answer, estimate each operand.
686 => 700
695 => 700
700 + 700 = 1400
#ProblemCorrect AnswerYour Answer
2
997
+ 702
Estimate
Solution
To get the estimated answer, estimate each operand.
997 => 1000
702 => 700
1000 + 700 = 1700

Complexity=5000

Estimate the sum using the highest practical magnitude.
Example 1: 53 + 19 => 50 + 20
Example 2: 123 + 57 => 120 + 60
Example 3: 1598 + 2301 => 2000 + 2000
#ProblemCorrect AnswerYour Answer
1
3315
+ 3509
Estimate
Solution
To get the estimated answer, estimate each operand.
3315 => 3000
3509 => 4000
3000 + 4000 = 7000
#ProblemCorrect AnswerYour Answer
2
3443
+ 4050
Estimate
Solution
To get the estimated answer, estimate each operand.
3443 => 3000
4050 => 4000
3000 + 4000 = 7000

Complexity=10000

Estimate the sum using the highest practical magnitude.
Example 1: 53 + 19 => 50 + 20
Example 2: 123 + 57 => 120 + 60
Example 3: 1598 + 2301 => 2000 + 2000
#ProblemCorrect AnswerYour Answer
1
7402
+ 8573
Estimate
Solution
To get the estimated answer, estimate each operand.
7402 => 7000
8573 => 9000
7000 + 9000 = 16000
#ProblemCorrect AnswerYour Answer
2
7086
+ 9135
Estimate
Solution
To get the estimated answer, estimate each operand.
7086 => 7000
9135 => 9000
7000 + 9000 = 16000

Complexity=20000

Estimate the sum using the highest practical magnitude.
Example 1: 53 + 19 => 50 + 20
Example 2: 123 + 57 => 120 + 60
Example 3: 1598 + 2301 => 2000 + 2000
#ProblemCorrect AnswerYour Answer
1
18792
+ 19516
Estimate
Solution
To get the estimated answer, estimate each operand.
18792 => 20000
19516 => 20000
20000 + 20000 = 40000
#ProblemCorrect AnswerYour Answer
2
10785
+ 9017
Estimate
Solution
To get the estimated answer, estimate each operand.
10785 => 11000
9017 => 9000
11000 + 9000 = 20000
When numbers have different magnitudes, round each number to the next highest magnitude, such as in this problem.

Complexity=100000

Estimate the sum using the highest practical magnitude.
Example 1: 53 + 19 => 50 + 20
Example 2: 123 + 57 => 120 + 60
Example 3: 1598 + 2301 => 2000 + 2000
#ProblemCorrect AnswerYour Answer
1
99872
+ 97079
Estimate
Solution
To get the estimated answer, estimate each operand.
99872 => 100000
97079 => 100000
100000 + 100000 = 200000
#ProblemCorrect AnswerYour Answer
2
67284
+ 72255
Estimate
Solution
To get the estimated answer, estimate each operand.
67284 => 70000
72255 => 70000
70000 + 70000 = 140000

MathScore.com

Copyright Accurate Learning Systems Corporation 2008.
MathScore is a registered trademark.