Math Practice Online > free > lessons > Texas > 8th grade > Cylinders

These sample problems below for Cylinders were generated by the MathScore.com engine.

## Sample Problems For Cylinders

### Complexity=1

Find the surface area and volume. Answer with proper units. To represent m2, use sq m. To answer with π, use 'pi'. Sample area: 5pi sq m. Sample volume: 5pi cu m
 1 Surface Area = Volume = 2 Surface Area = Volume =

### Complexity=2

Find the surface area and volume. Answer with proper units. To represent m2, use sq m. To answer with π, use 'pi'. Sample area: 5pi sq m. Sample volume: 5pi cu m
 1 Surface Area = Volume = 2 Surface Area = Volume =

### Complexity=1

Find the surface area and volume. Answer with proper units. To represent m2, use sq m. To answer with π, use 'pi'. Sample area: 5pi sq m. Sample volume: 5pi cu m
1 Surface Area =
Volume =
Solution
The surface area of a cylinder is the area of the bottom and top circles and the area of the side of the cylinder. This can be expressed as follows:
SA = 2πrh + 2πr2
SA = 2π × (2cm) × (2 cm) + 2π × (2 cm)2
SA = 2π × (4 cm2) + 2π × (4 cm2)
SA = 8π cm2 + 8π cm2
SA = 16π cm2

The volume of a cylinder is the area of the base circle times the height of the cylinder.
V = bh = πr2h
V = π × (2 cm)2 × (2 cm)
V = π × (4 cm2) × (2 cm)
V = π × (8 cm3)
V = 8π cm3
2 Surface Area =
Volume =
Solution
The surface area of a cylinder is the area of the bottom and top circles and the area of the side of the cylinder. This can be expressed as follows:
SA = 2πrh + 2πr2
SA = 2π × (3in) × (3 in) + 2π × (3 in)2
SA = 2π × (9 in2) + 2π × (9 in2)
SA = 18π in2 + 18π in2
SA = 36π in2

The volume of a cylinder is the area of the base circle times the height of the cylinder.
V = bh = πr2h
V = π × (3 in)2 × (3 in)
V = π × (9 in2) × (3 in)
V = π × (27 in3)
V = 27π in3

### Complexity=2

Find the surface area and volume. Answer with proper units. To represent m2, use sq m. To answer with π, use 'pi'. Sample area: 5pi sq m. Sample volume: 5pi cu m
1 Surface Area =
Volume =
Solution
The surface area of a cylinder is the area of the bottom and top circles and the area of the side of the cylinder. This can be expressed as follows:
SA = 2πrh + 2πr2
SA = 2π × (2in) × (4 in) + 2π × (2 in)2
SA = 2π × (8 in2) + 2π × (4 in2)
SA = 16π in2 + 8π in2
SA = 24π in2

The volume of a cylinder is the area of the base circle times the height of the cylinder.
V = bh = πr2h
V = π × (2 in)2 × (4 in)
V = π × (4 in2) × (4 in)
V = π × (16 in3)
V = 16π in3
2 Surface Area =
Volume =
Solution
The surface area of a cylinder is the area of the bottom and top circles and the area of the side of the cylinder. This can be expressed as follows:
SA = 2πrh + 2πr2
SA = 2π × (8cm) × (6 cm) + 2π × (8 cm)2
SA = 2π × (48 cm2) + 2π × (64 cm2)
SA = 96π cm2 + 128π cm2
SA = 224π cm2

The volume of a cylinder is the area of the base circle times the height of the cylinder.
V = bh = πr2h
V = π × (8 cm)2 × (6 cm)
V = π × (64 cm2) × (6 cm)
V = π × (384 cm3)
V = 384π cm3

MathScore.com

Copyright Accurate Learning Systems Corporation 2008.
MathScore is a registered trademark.