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These sample problems below for Triangular Prisms were generated by the MathScore.com engine.

## Sample Problems For Triangular Prisms

### Complexity=1

Find the volume of the triangular prisms given. Answer with proper units. To represent m3, use cu m. Sample answer: 5 cu m
 1.   volume = 2.   volume =

### Complexity=2

Find the volume of the triangular prisms given. Answer with proper units. To represent m3, use cu m. Sample answer: 5 cu m
 1.   volume = 2.   volume =

### Complexity=1

Find the volume of the triangular prisms given. Answer with proper units. To represent m3, use cu m. Sample answer: 5 cu m
1 volume =
Solution
The volume of a triangular prism is the area of the triangle times the length perpendicular to the triangle. In our case, the length perpendicular to the triangle is the width.
Area of triangle = 1/2bh =
1/2(length)(height) =
(1/2)(2 cm)(2cm) =
2 cm2
V = Triangle Area × width =
2 cm2 × 2 cm =
4cm3
2 volume =
Solution
The volume of a triangular prism is the area of the triangle times the length perpendicular to the triangle. In our case, the length perpendicular to the triangle is the width.
Area of triangle = 1/2bh =
1/2(length)(height) =
(1/2)(2 in)(3in) =
3 in2
V = Triangle Area × width =
3 in2 × 4 in =
12in3

### Complexity=2

Find the volume of the triangular prisms given. Answer with proper units. To represent m3, use cu m. Sample answer: 5 cu m
1 volume =
Solution
The volume of a triangular prism is the area of the triangle times the length perpendicular to the triangle. In our case, the length perpendicular to the triangle is the width.
Area of triangle = 1/2bh =
1/2(length)(height) =
(1/2)(3 in)(6in) =
9 in2
V = Triangle Area × width =
9 in2 × 3 in =
27in3
2 volume =
Solution
The volume of a triangular prism is the area of the triangle times the length perpendicular to the triangle. In our case, the length perpendicular to the triangle is the width.
Area of triangle = 1/2bh =
1/2(length)(height) =
(1/2)(4 cm)(7cm) =
14 cm2
V = Triangle Area × width =
14 cm2 × 4 cm =
56cm3

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