Math Practice Problems

Circle Area - Sample Math Practice Problems

The math problems below can be generated by MathScore.com, a math practice program for schools and individual families. References to complexity and mode refer to the overall difficulty of the problems as they appear in the main program. In the main program, all problems are automatically graded and the difficulty adapts dynamically based on performance. Answers to these sample questions appear at the bottom of the page. This page does not grade your responses.

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Complexity=4, Mode=exact

Find the area in terms of π. Type "pi" in for π so that a correct answer would look like 7pi sq m

Area:

Complexity=6, Mode=exact

Find the area in terms of π. Type "pi" in for π so that a correct answer would look like 7pi sq m

Area:

Complexity=8, Mode=exact

Find the area in terms of π. Type "pi" in for π so that a correct answer would look like 7pi sq m

Area:

Complexity=4, Mode=fraction

Find the area. Use 22/7 as an approximation for π. A correct answer would look like 14.5 sq cm.

Area:

Complexity=4

Find the area. Use 3.14 as an approximation for π. A correct answer would look like 4.785 sq in

Area:

Answers

Complexity=4, Mode=exact

Find the area in terms of π. Type "pi" in for π so that a correct answer would look like 7pi sq m

#	Problem	Correct Answer	Your Answer
1		Area:
Solution Area = π × (radius)² A = πr² Plugging values into the equation, we have: A = π(4 in)² A = &pi(16 in²) A = 16π in²

#	Problem	Correct Answer	Your Answer
2		Area:
Solution Area = π × (radius)² A = πr² Plugging values into the equation, we have: A = π(2 mm)² A = &pi(4 mm²) A = 4π mm²

Complexity=6, Mode=exact

Find the area in terms of π. Type "pi" in for π so that a correct answer would look like 7pi sq m

#	Problem	Correct Answer	Your Answer
1		Area:
Solution Area = π × (radius)² A = πr² Plugging values into the equation, we have: A = π(1 km)² A = &pi(1 km²) A = 1π km²

#	Problem	Correct Answer	Your Answer
2		Area:
Solution Area = π × (radius)² A = πr² Plugging values into the equation, we have: A = π(5 ft)² A = &pi(25 ft²) A = 25π ft²

Complexity=8, Mode=exact

Find the area in terms of π. Type "pi" in for π so that a correct answer would look like 7pi sq m

#	Problem	Correct Answer	Your Answer
1		Area:
Solution Area = π × (radius)² A = πr² Since we have that the diameter is 3 km, we divide it by 2 to get the radius which then is 1.5 km. Plugging values into the equation, we have: A = π(1.5 km)² A = &pi(2.25 km²) A = 2.25π km²

#	Problem	Correct Answer	Your Answer
2		Area:
Solution Area = π × (radius)² A = πr² Plugging values into the equation, we have: A = π(1 m)² A = &pi(1 m²) A = 1π m²

Complexity=4, Mode=fraction

Find the area. Use 22/7 as an approximation for π. A correct answer would look like 14.5 sq cm.

#	Problem	Correct Answer	Your Answer
1		Area:
Solution Area = π × (radius)² A = πr² Since we have that the diameter is 14 mm, we divide it by 2 to get the radius which then is 7 mm. Plugging values into the equation, we have: A = π(7 mm)² A = (22/7) × (154 mm²) 484 mm²

#	Problem	Correct Answer	Your Answer
2		Area:
Solution Area = π × (radius)² A = πr² Since we have that the diameter is 7 yd, we divide it by 2 to get the radius which then is 3.5 yd. Plugging values into the equation, we have: A = π(3.5 yd)² A = (22/7) × (38.5 yd²) 121 yd²

Complexity=4

Find the area. Use 3.14 as an approximation for π. A correct answer would look like 4.785 sq in

#	Problem	Correct Answer	Your Answer
1		Area:
Solution Area = π × (radius)² A = πr² Plugging values into the equation, we have: A = π(1 ft)² A = 3.14 × (3.14 ft²) 9.8596 ft²

#	Problem	Correct Answer	Your Answer
2		Area:
Solution Area = π × (radius)² A = πr² Plugging values into the equation, we have: A = π(3 mm)² A = 3.14 × (28.26 mm²) 88.7364 mm²

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