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Circle Circumference - Sample Math Practice Problems

The math problems below can be generated by MathScore.com, a math practice program for schools and individual families. References to complexity and mode refer to the overall difficulty of the problems as they appear in the main program. In the main program, all problems are automatically graded and the difficulty adapts dynamically based on performance. Answers to these sample questions appear at the bottom of the page. This page does not grade your responses.

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Complexity=4, Mode=exact

Find the circumference in terms of π. Type "pi" in for π so that a correct answer would look like 7pi m.
1.   Circumference:
2.   Circumference:

Complexity=6, Mode=exact

Find the circumference in terms of π. Type "pi" in for π so that a correct answer would look like 7pi m.
1.   Circumference:
2.   Circumference:

Complexity=8, Mode=exact

Find the circumference in terms of π. Type "pi" in for π so that a correct answer would look like 7pi m.
1.   Circumference:
2.   Circumference:

Complexity=4, Mode=fraction

Find the circumference. Use 22/7 as an approximation for π. A correct answer would look like 14.5 cm.
1.   Circumference:
2.   Circumference:

Complexity=4

Find the circumference. Use 3.14 as an approximation for π. A correct answer would look like 4.78 in.
1.   Circumference:
2.   Circumference:

Answers


Complexity=4, Mode=exact

Find the circumference in terms of π. Type "pi" in for π so that a correct answer would look like 7pi m.
#ProblemCorrect AnswerYour Answer
1 Circumference:
Solution
Circumference = π × diameter
C = πd
Since we have that the radius is 2 cm, we multiply it by 2 to get the diameter which then is 4 cm.
Plugging values into the equation, we have:
C = π(4 cm)
C = 4π cm
#ProblemCorrect AnswerYour Answer
2 Circumference:
Solution
Circumference = π × diameter
C = πd
Plugging values into the equation, we have:
C = π(4 m)
C = 4π m

Complexity=6, Mode=exact

Find the circumference in terms of π. Type "pi" in for π so that a correct answer would look like 7pi m.
#ProblemCorrect AnswerYour Answer
1 Circumference:
Solution
Circumference = π × diameter
C = πd
Since we have that the radius is 2 in, we multiply it by 2 to get the diameter which then is 4 in.
Plugging values into the equation, we have:
C = π(4 in)
C = 4π in
#ProblemCorrect AnswerYour Answer
2 Circumference:
Solution
Circumference = π × diameter
C = πd
Since we have that the radius is 5 cm, we multiply it by 2 to get the diameter which then is 10 cm.
Plugging values into the equation, we have:
C = π(10 cm)
C = 10π cm

Complexity=8, Mode=exact

Find the circumference in terms of π. Type "pi" in for π so that a correct answer would look like 7pi m.
#ProblemCorrect AnswerYour Answer
1 Circumference:
Solution
Circumference = π × diameter
C = πd
Plugging values into the equation, we have:
C = π(4 mi)
C = 4π mi
#ProblemCorrect AnswerYour Answer
2 Circumference:
Solution
Circumference = π × diameter
C = πd
Plugging values into the equation, we have:
C = π(4 mi)
C = 4π mi

Complexity=4, Mode=fraction

Find the circumference. Use 22/7 as an approximation for π. A correct answer would look like 14.5 cm.
#ProblemCorrect AnswerYour Answer
1 Circumference:
Solution
Circumference = π × diameter
C = πd
Since we have that the radius is 28 m, we multiply it by 2 to get the diameter which then is 56 m.
Plugging values into the equation, we have:
C = π(56 m)
C = (22/7) × (56 m)
C = 176 m
#ProblemCorrect AnswerYour Answer
2 Circumference:
Solution
Circumference = π × diameter
C = πd
Plugging values into the equation, we have:
C = π(21 mi)
C = (22/7) × (21 mi)
C = 66 mi

Complexity=4

Find the circumference. Use 3.14 as an approximation for π. A correct answer would look like 4.78 in.
#ProblemCorrect AnswerYour Answer
1 Circumference:
Solution
Circumference = π × diameter
C = πd
Plugging values into the equation, we have:
C = π(4 yd)
C = 3.14 × (4 yd)
12.56 yd
#ProblemCorrect AnswerYour Answer
2 Circumference:
Solution
Circumference = π × diameter
C = πd
Since we have that the radius is 3 in, we multiply it by 2 to get the diameter which then is 6 in.
Plugging values into the equation, we have:
C = π(6 in)
C = 3.14 × (6 in)
18.84 in
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