Math Practice Problems - Stem And Leaf Plots

Stem And Leaf Plots - Sample Math Practice Problems

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Complexity=5

Calculate the mean of the data represented by the following stem and leaf plots.

Data Values
Stem	Leaf
1	1
3	3
8	2, 5
9	3

Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:

Data Values
Stem	Leaf
1	0
4	6, 9
5	7
7	4

Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:

Complexity=8

Calculate the mean of the data represented by the following stem and leaf plots.

Data Values
Stem	Leaf
0	2
2	1
3	8
9	1

Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:

Data Values
Stem	Leaf
0	8, 9
3	0
8	9
9	3, 5

Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:

Answers

Complexity=5

Calculate the mean of the data represented by the following stem and leaf plots.

Problem

Correct Answer

Your Answer

Data Values
Stem	Leaf
1	1
3	3
8	2, 5
9	3

Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:

Solution
Arithmetic Mean = sum of values / number of values = (11 + 33 + 82 + 85 + 93) / 5 = 60.8
Median = middle term of values = middle of (11, 33, 82, 85, 93) = 82
Range = largest value - smallest value = 93 - 11 = 82
Lower Quartile = median of lower half of data values = middle of (11, 33) = (11 + 33) / 2 = 22
Upper Quartile = median of upper half of data values = middle of (85, 93) = (85 + 93) / 2 = 89

Problem

Correct Answer

Your Answer

Data Values
Stem	Leaf
1	0
4	6, 9
5	7
7	4

Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:

Solution
Arithmetic Mean = sum of values / number of values = (10 + 46 + 49 + 57 + 74) / 5 = 47.2
Median = middle term of values = middle of (10, 46, 49, 57, 74) = 49
Range = largest value - smallest value = 74 - 10 = 64
Lower Quartile = median of lower half of data values = middle of (10, 46) = (10 + 46) / 2 = 28
Upper Quartile = median of upper half of data values = middle of (57, 74) = (57 + 74) / 2 = 65.5

Complexity=8

Calculate the mean of the data represented by the following stem and leaf plots.

Problem

Correct Answer

Your Answer

Data Values
Stem	Leaf
0	2
2	1
3	8
9	1

Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:

Solution
Arithmetic Mean = sum of values / number of values = (2 + 21 + 38 + 91) / 4 = 38
Median = middle term of values = middle of (2, 21, 38, 91) = (21 + 38)/2 =29.5
Range = largest value - smallest value = 91 - 2 = 89
Lower Quartile = median of lower half of data values = middle of (2, 21) = (2 + 21) / 2 = 11.5
Upper Quartile = median of upper half of data values = middle of (38, 91) = (38 + 91) / 2 = 64.5

Problem

Correct Answer

Your Answer

Data Values
Stem	Leaf
0	8, 9
3	0
8	9
9	3, 5

Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:

Solution
Arithmetic Mean = sum of values / number of values = (8 + 9 + 30 + 89 + 93 + 95) / 6 = 54
Median = middle term of values = middle of (8, 9, 30, 89, 93, 95) = (30 + 89)/2 =59.5
Range = largest value - smallest value = 95 - 8 = 87
Lower Quartile = median of lower half of data values = middle of (8, 9, 30) = 9
Upper Quartile = median of upper half of data values = middle of (89, 93, 95) = 93

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