## Triangular Prisms - Sample Math Practice Problems

The math problems below can be generated by MathScore.com, a math practice program for schools and individual families. References to complexity and mode refer to the overall difficulty of the problems as they appear in the main program. In the main program, all problems are automatically graded and the difficulty adapts dynamically based on performance. Answers to these sample questions appear at the bottom of the page. This page does not grade your responses.

See some of our other supported math practice problems.

### Complexity=1

Find the volume of the triangular prisms given. Answer with proper units. To represent m3, use cu m. Sample answer: 5 cu m
 1.   volume = 2.   volume =

### Complexity=2

Find the volume of the triangular prisms given. Answer with proper units. To represent m3, use cu m. Sample answer: 5 cu m
 1.   volume = 2.   volume =

### Complexity=1

Find the volume of the triangular prisms given. Answer with proper units. To represent m3, use cu m. Sample answer: 5 cu m
1 volume =
Solution
The volume of a triangular prism is the area of the triangle times the length perpendicular to the triangle. In our case, the length perpendicular to the triangle is the width.
Area of triangle = 1/2bh =
1/2(length)(height) =
(1/2)(3 ft)(2ft) =
3 ft2
V = Triangle Area × width =
3 ft2 × 1 ft =
3ft3
2 volume =
Solution
The volume of a triangular prism is the area of the triangle times the length perpendicular to the triangle. In our case, the length perpendicular to the triangle is the width.
Area of triangle = 1/2bh =
1/2(length)(height) =
(1/2)(2 yd)(1yd) =
1 yd2
V = Triangle Area × width =
1 yd2 × 3 yd =
3yd3

### Complexity=2

Find the volume of the triangular prisms given. Answer with proper units. To represent m3, use cu m. Sample answer: 5 cu m
1 volume =
Solution
The volume of a triangular prism is the area of the triangle times the length perpendicular to the triangle. In our case, the length perpendicular to the triangle is the width.
Area of triangle = 1/2bh =
1/2(length)(height) =
(1/2)(2 yd)(6yd) =
6 yd2
V = Triangle Area × width =
6 yd2 × 1 yd =
6yd3
2 volume =
Solution
The volume of a triangular prism is the area of the triangle times the length perpendicular to the triangle. In our case, the length perpendicular to the triangle is the width.
Area of triangle = 1/2bh =
1/2(length)(height) =
(1/2)(1 yd)(3yd) =
1.5 yd2
V = Triangle Area × width =
1.5 yd2 × 2 yd =
3yd3