Math Practice Problems - Word Problems With Remainders

Word Problems With Remainders - Sample Math Practice Problems

The math problems below can be generated by MathScore.com, a math practice program for schools and individual families. References to complexity and mode refer to the overall difficulty of the problems as they appear in the main program. In the main program, all problems are automatically graded and the difficulty adapts dynamically based on performance. Answers to these sample questions appear at the bottom of the page. This page does not grade your responses.

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Complexity=1

Solve.

Miguel divides 101 marbles equally among 8
friends.

a. How many marbles does each friend get?
b. How many marbles are left over?

a. marbles
b. marbles

Jose buys 12 peppermints and 2 goody bags for his
party. He needs to put an equal amount in each
bag.

a. How many peppermints can be put in each goody bag?
b. How many peppermints are left over?

a. peppermints
b. peppermints

Complexity=2

Solve.

1. A group of 55 people signed up for guitar
lessons. Each class can have a maximum of 6
students. What is the least number of classes
needed?
classes

2. Mike has $21. If T-shirts cost $4 each, then how
many T-shirts can he buy?
T-shirts

Complexity=3

Solve.

1. Pearl divided 58 pinwheels equally into 6 jars.
She gave away all but 1 jar and the leftover
pinwheels. How many pinwheels did she keep?
pinwheels

2. Cindy filled some boxes with 8 peppermints each
and had 2 peppermints left over. If she started
with 34 peppermints, how many boxes did she fill?
boxes

Answers

Complexity=1

Solve.

#	Problem	Correct Answer	Your Answer
1	Miguel divides 101 marbles equally among 8 friends. a. How many marbles does each friend get? b. How many marbles are left over?	a. marbles b. marbles
Solution 101 ÷ 8 = 12 r 5 Each friend gets 12 marbles with 5 left over.

#	Problem	Correct Answer	Your Answer
2	Jose buys 12 peppermints and 2 goody bags for his party. He needs to put an equal amount in each bag. a. How many peppermints can be put in each goody bag? b. How many peppermints are left over?	a. peppermints b. peppermints
Solution 2 divides evenly into 12. Each goody bag can have 12 ÷ 2 = 6 peppermints, and no peppermints are left over.

Complexity=2

Solve.

#	Problem	Correct Answer	Your Answer
1	A group of 55 people signed up for guitar lessons. Each class can have a maximum of 6 students. What is the least number of classes needed?	classes
Solution 55 ÷ 6 = 9 r 1 If there are only 9 classes, 1 person will not be able to take guitar lessons. So, 10 classes are needed.

#	Problem	Correct Answer	Your Answer
2	Mike has $21. If T-shirts cost $4 each, then how many T-shirts can he buy?	T-shirts
Solution 21 ÷ 4 = 5 r 1 Mike can only buy 5 T-shirts because $1 is not enough money left over to buy another.

Complexity=3

Solve.

Problem

Correct Answer

Your Answer

Pearl divided 58 pinwheels equally into 6 jars.
She gave away all but 1 jar and the leftover
pinwheels. How many pinwheels did she keep?

pinwheels

Solution
58 ÷ 6 = 9 r 4
58 pinwheels divide into 6 jars of 9 pinwheels each with 4 pinwheels left over.

Pearl kept 1 jar and the leftovers.

1 jar	+	leftovers	=
9 pinwheels	+	4 pinwheels	=	13 pinwheels

So Pearl kept 13 pinwheels.

#	Problem	Correct Answer	Your Answer
2	Cindy filled some boxes with 8 peppermints each and had 2 peppermints left over. If she started with 34 peppermints, how many boxes did she fill?	boxes
Solution 34 peppermints - 2 peppermints = 32 peppermints in boxes 32 peppermints ÷ 8 peppermints / box = 4 boxes

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