## Word Problems With Remainders - Sample Math Practice Problems

The math problems below can be generated by MathScore.com, a math practice program for schools and individual families. References to complexity and mode refer to the overall difficulty of the problems as they appear in the main program. In the main program, all problems are automatically graded and the difficulty adapts dynamically based on performance. Answers to these sample questions appear at the bottom of the page. This page does not grade your responses.

See some of our other supported math practice problems.

### Complexity=1

Solve.
 1 Miguel divides 101 marbles equally among 8 friends.a. How many marbles does each friend get? b. How many marbles are left over? a. marbles   b. marbles 2 Jose buys 12 peppermints and 2 goody bags for his party. He needs to put an equal amount in each bag.a. How many peppermints can be put in each goody bag? b. How many peppermints are left over? a. peppermints   b. peppermints

### Complexity=2

Solve.
 1.   A group of 55 people signed up for guitar lessons. Each class can have a maximum of 6 students. What is the least number of classes needed? classes 2.   Mike has \$21. If T-shirts cost \$4 each, then how many T-shirts can he buy? T-shirts

### Complexity=3

Solve.
 1.   Pearl divided 58 pinwheels equally into 6 jars. She gave away all but 1 jar and the leftover pinwheels. How many pinwheels did she keep? pinwheels 2.   Cindy filled some boxes with 8 peppermints each and had 2 peppermints left over. If she started with 34 peppermints, how many boxes did she fill? boxes

### Complexity=1

Solve.
1Miguel divides 101 marbles equally among 8
friends.
a. How many marbles does each friend get?
b. How many marbles are left over?

a. marbles
b. marbles
Solution
101 ÷ 8 = 12 r 5
Each friend gets 12 marbles with 5 left over.
2Jose buys 12 peppermints and 2 goody bags for his
party. He needs to put an equal amount in each
bag.
a. How many peppermints can be put in each goody bag?
b. How many peppermints are left over?

a. peppermints
b. peppermints
Solution
2 divides evenly into 12.
Each goody bag can have 12 ÷ 2 = 6 peppermints, and no peppermints are left over.

### Complexity=2

Solve.
1A group of 55 people signed up for guitar
lessons. Each class can have a maximum of 6
students. What is the least number of classes
needed?
classes
Solution
55 ÷ 6 = 9 r 1
If there are only 9 classes, 1 person will not be able to take guitar lessons.
So, 10 classes are needed.
2Mike has \$21. If T-shirts cost \$4 each, then how
T-shirts
Solution
21 ÷ 4 = 5 r 1
Mike can only buy 5 T-shirts because \$1 is not enough money left over to buy another.

### Complexity=3

Solve.
1Pearl divided 58 pinwheels equally into 6 jars.
She gave away all but 1 jar and the leftover
pinwheels. How many pinwheels did she keep?
pinwheels
Solution
58 ÷ 6 = 9 r 4
58 pinwheels divide into 6 jars of 9 pinwheels each with 4 pinwheels left over.

Pearl kept 1 jar and the leftovers.
 1 jar + leftovers = 9 pinwheels + 4 pinwheels = 13 pinwheels

So Pearl kept 13 pinwheels.